Interesting. I know that Pi is an irrational number. Which is to say that it has a non repeating, non terminating decimal place..It doesn't have an EXACT place on a number line..Like the number two..
I put the sqrt(pi) into the calculator..I came up with 1.772453851
Now that I think about it more...There is no way that it could have an exact square root, as pi itself is irrational...There are no two rational numbers that can be multiplied together, that will yield an irrational number...
2007-04-20 21:56:54
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answer #1
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answered by RScott 3
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Pi is an infinately long number, so there is no accurate square root, but you can find the square root of numbers like 9pi^2, which may i add is 3pi
2007-04-20 22:02:13
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answer #2
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answered by David T 2
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Apparently! According to a website I've just looked at the square root of pi is 1.7724538090
2007-04-20 22:08:04
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answer #3
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answered by Toffee Jo 1
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There has never been an exact number of pi. When calculated with a computer it creates over a trillion digits.
2007-04-20 22:03:26
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answer #4
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answered by theblackenedphoenix 4
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of course there is, Pi is a number, and not a negative number, so it has a square root.
2007-04-20 21:54:04
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answer #5
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answered by Anonymous
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Yes, there is, although pi is an irrational number, which is never-ending. Since pi is approx. 3.141592653589793 23846264338327950288419716939937510 , the sqrt of it is approx 1.772453850905516027298167483341.
2007-04-20 22:04:18
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answer #6
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answered by Az 3
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Ya it has an answer....
afterall every number has a squreroot through Complex nubers we can express a squareroot value for even a negative intiger
2007-04-20 22:53:52
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answer #7
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answered by Umar N 1
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Yes! pi is a number. 1.772453851...
2007-04-20 21:55:10
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answer #8
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answered by Anonymous
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Yes but irrational number meaning having decimals without
1.77245....
2007-04-20 21:59:11
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answer #9
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answered by maussy 7
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Yes the numers the others are giving are right however it is true that since it is irrational, it can not be exact. Here is a webpages to help you:
http://mathforum.org/library/drmath/view/58261.html
2007-04-20 22:07:27
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answer #10
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answered by NANOGIRL 2
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