When calcium is heated, a orange spectral line whose energy is 3.26 10-19 J per photon is produced.
(a) What is the frequency of this light?
(b) What is the wavelength of this light?
2007-04-20 19:22:58 · 3 answers · asked by sydney 1 in Science & Mathematics ➔ Chemistry
An orange spectral line means it absorbed the complement of orange color. Find the complement of orange color and its wavelength of absorption. That will be the wavelength answer to one of your questions.
Then use the following formula: E = hv.
h is Planck's constant. h = 6.626 x 10 -34
v is the frequency of light.
Manipulate the formula to get the answer to the first question.
2007-04-20 19:35:01 · answer #1 · answered by laila_eic 2 · 0⤊ 0⤋
Solve the part a using equation
E = hv
Where, E = 3.26 10-19 J per photon
h= Planck's constant.
While for the b part,
E = hc / wavelength
c = 3 * 10 +8 cm/s
2007-04-20 19:44:19 · answer #2 · answered by indiavision 4 · 0⤊ 0⤋
Use the eqn E = hc/lambda
2007-04-20 19:45:33 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 0⤋