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Solve by the substitution method.
2x + 2y =6
-7x + y =19

What is the solution of the system?______
type an ordered pair

2007-04-20 18:37:14 · 11 answers · asked by Anonymous in Science & Mathematics Mathematics

11 answers

solve 2x+2y=6 for x
x = 3-y

use 3-y as a substitution for x in the second equation
-7(3 - y) + y = 19
solve for y
y = 5
x= 3-y = 3-5 = -2

x = -2
y = 5

(-2,5)

2007-04-20 18:42:41 · answer #1 · answered by James H 2 · 1 0

2x + 2y = 6- - - - - - -Equation 1
- 7x + y = 10- - - - - -Equation 2
- - - - - - - - - --

Substitute Method eqution 2

- 7x + y = 19

- 7x + y + 7x = 7x + 19

y = 7x + 19

Substitute the y value into equation 1

- - - - - - - - - - - - - - - - - - - - - - - - - - - -

2x + 2y = 6

2x + 2(7x + 19) = 6

2x + 14x + 38 = 6

16x + 38 = 6

16x + 38 - 38 = 6 - 38

16x = - 32

16x / 16 = - 32 / 16

x = - 32 / 16

x= - 2

Insert the x value into eqution 1

- - - - - - - - - - - - - - - - - - - - - - -

2x + 2y = 6

2(- 2) + 2y = 6

- 4 + 2y = 6

- 4 + 2y + 4 = 6 + 4

2y = 10

2y / 2 = 10 / 2

y = 10/ 2

y = 5

Insert the y value into equation 1

- - - - - - - - - - - - - - - - - - - - - - - - -

Check for equation 1

2x + 2y = 6

2(- 2) + 2(5) = 6

- 4 + 10 = 6

6 = 6

- - - - - - - - -

Check for equation 2

- 7x + y = 19

- 7(- 2) + 5 = 19

- (- 14) + 5 = 19

14 + 5 = 19

19 = 19

- - - - - - - - -

Both equtions balance

The solution set is { - 2, 5 }

- - - - - - - - - -s-

2007-04-21 06:35:44 · answer #2 · answered by SAMUEL D 7 · 0 0

Actually I'm not an alegbra masters, I'm an algebra master. But I'll help you.

-7x + y =19 => y = 7x + 19

Substitute y = 7x + 19 to the first equation

2x + 2y = 6 => 2x + 2*(7x + 19) = 6
2x + 14x + 38 = 6
16x = -32
x = -2
y = 7 * (-2) + 19 = 5

Solution: ( -2, 5 )

2007-04-21 19:39:06 · answer #3 · answered by - 1 · 0 0

2x+2y=6 2 times 0 +2 times three=6 -7 times 0 + 19=19

2007-04-21 01:46:56 · answer #4 · answered by shawn c 1 · 0 0

2y = 6 - 2x.

y = (6 - 2x)/2 = 3-x.

-7x + (y = 3 - x) = 19.

-8x + 3 = 19.

-8x = 16.

x = 16/(-8) = -2


2y = 6- 2x.

2y = 6 - 2(x = -2)

2y = 6 + 4 = 10.

y = 5.


Solution set (x, y) of the system = (-2, 5)

2007-04-21 01:45:42 · answer #5 · answered by Mark 6 · 0 0

2x + 2y = 6 --> 1st equation
-7x + y = 19 --> 2nd Equation
2nd Equation become :
y = 7x + 19 --> 3rd Equation
Substitute y to 1st Equation
2x + 2y = 19 become
2x + 2(7x + 19) = 6
2x + 14x + 38 = 6
16x = -32
x = -2
Substitute x to 3rd Equation,
y = 7*(-2) + 19
y = 5
So,
x = -2, y = 5

2007-04-21 01:59:10 · answer #6 · answered by wangsacl 4 · 0 0

given question: 2x+2y=6 ; -7x+y=19
using the 2nd equation to get y: y=7x+19
substitute to 1st equation: 2x+2(7x+19)=6
2x+14x+38=6
16x=-32
x=-2
then substitute x=-2 to the 2nd equation: -7(-2)+y=19
y=5
answer: {-2,5}

2007-04-21 01:58:54 · answer #7 · answered by violettorose 3 · 0 0

y=5,x=-2

2007-04-21 01:40:38 · answer #8 · answered by Tiruvenkatan R 3 · 0 0

okay you have to first make it so one of your variables cancels out... i would choose to multiply the second system by -2

so by doing that you get a new pair
2x+2y=6
14x-2y=-38

then you add downwards

16x=32 >solve for x by dividing
x=2 >insert the answer for x in the original problem

2(2)+2y=6
4+2y=6 >solve for y

2y=2
y=1

your ordered pair is (2,1)

2007-04-21 01:45:49 · answer #9 · answered by Alexandra P 1 · 1 0

shoot i took algebra last year in 7th grade an i forgot. all i remember is multiply the bottom by negative two to ... wait i remember now. multiply the bottom equation by negative 2 to cancel out the 2y. solve for x and then substitute in the other equation. then figure out y. i'm not giving you the answer because then that would be cheating!

2007-04-21 01:43:14 · answer #10 · answered by Anonymous · 1 0

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