solve 2x+2y=6 for x
x = 3-y
use 3-y as a substitution for x in the second equation
-7(3 - y) + y = 19
solve for y
y = 5
x= 3-y = 3-5 = -2
x = -2
y = 5
(-2,5)
2007-04-20 18:42:41
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answer #1
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answered by James H 2
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2x + 2y = 6- - - - - - -Equation 1
- 7x + y = 10- - - - - -Equation 2
- - - - - - - - - --
Substitute Method eqution 2
- 7x + y = 19
- 7x + y + 7x = 7x + 19
y = 7x + 19
Substitute the y value into equation 1
- - - - - - - - - - - - - - - - - - - - - - - - - - - -
2x + 2y = 6
2x + 2(7x + 19) = 6
2x + 14x + 38 = 6
16x + 38 = 6
16x + 38 - 38 = 6 - 38
16x = - 32
16x / 16 = - 32 / 16
x = - 32 / 16
x= - 2
Insert the x value into eqution 1
- - - - - - - - - - - - - - - - - - - - - - -
2x + 2y = 6
2(- 2) + 2y = 6
- 4 + 2y = 6
- 4 + 2y + 4 = 6 + 4
2y = 10
2y / 2 = 10 / 2
y = 10/ 2
y = 5
Insert the y value into equation 1
- - - - - - - - - - - - - - - - - - - - - - - - -
Check for equation 1
2x + 2y = 6
2(- 2) + 2(5) = 6
- 4 + 10 = 6
6 = 6
- - - - - - - - -
Check for equation 2
- 7x + y = 19
- 7(- 2) + 5 = 19
- (- 14) + 5 = 19
14 + 5 = 19
19 = 19
- - - - - - - - -
Both equtions balance
The solution set is { - 2, 5 }
- - - - - - - - - -s-
2007-04-21 06:35:44
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answer #2
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answered by SAMUEL D 7
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Actually I'm not an alegbra masters, I'm an algebra master. But I'll help you.
-7x + y =19 => y = 7x + 19
Substitute y = 7x + 19 to the first equation
2x + 2y = 6 => 2x + 2*(7x + 19) = 6
2x + 14x + 38 = 6
16x = -32
x = -2
y = 7 * (-2) + 19 = 5
Solution: ( -2, 5 )
2007-04-21 19:39:06
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answer #3
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answered by - 1
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2x+2y=6 2 times 0 +2 times three=6 -7 times 0 + 19=19
2007-04-21 01:46:56
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answer #4
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answered by shawn c 1
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2y = 6 - 2x.
y = (6 - 2x)/2 = 3-x.
-7x + (y = 3 - x) = 19.
-8x + 3 = 19.
-8x = 16.
x = 16/(-8) = -2
2y = 6- 2x.
2y = 6 - 2(x = -2)
2y = 6 + 4 = 10.
y = 5.
Solution set (x, y) of the system = (-2, 5)
2007-04-21 01:45:42
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answer #5
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answered by Mark 6
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2x + 2y = 6 --> 1st equation
-7x + y = 19 --> 2nd Equation
2nd Equation become :
y = 7x + 19 --> 3rd Equation
Substitute y to 1st Equation
2x + 2y = 19 become
2x + 2(7x + 19) = 6
2x + 14x + 38 = 6
16x = -32
x = -2
Substitute x to 3rd Equation,
y = 7*(-2) + 19
y = 5
So,
x = -2, y = 5
2007-04-21 01:59:10
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answer #6
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answered by wangsacl 4
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given question: 2x+2y=6 ; -7x+y=19
using the 2nd equation to get y: y=7x+19
substitute to 1st equation: 2x+2(7x+19)=6
2x+14x+38=6
16x=-32
x=-2
then substitute x=-2 to the 2nd equation: -7(-2)+y=19
y=5
answer: {-2,5}
2007-04-21 01:58:54
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answer #7
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answered by violettorose 3
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y=5,x=-2
2007-04-21 01:40:38
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answer #8
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answered by Tiruvenkatan R 3
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okay you have to first make it so one of your variables cancels out... i would choose to multiply the second system by -2
so by doing that you get a new pair
2x+2y=6
14x-2y=-38
then you add downwards
16x=32 >solve for x by dividing
x=2 >insert the answer for x in the original problem
2(2)+2y=6
4+2y=6 >solve for y
2y=2
y=1
your ordered pair is (2,1)
2007-04-21 01:45:49
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answer #9
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answered by Alexandra P 1
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shoot i took algebra last year in 7th grade an i forgot. all i remember is multiply the bottom by negative two to ... wait i remember now. multiply the bottom equation by negative 2 to cancel out the 2y. solve for x and then substitute in the other equation. then figure out y. i'm not giving you the answer because then that would be cheating!
2007-04-21 01:43:14
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answer #10
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answered by Anonymous
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