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how many grams of potassium chloride (KCl) would be formed in the reaction : K2CO3 +2HCl ---> CO2 +H2O+2KCl?

if 3.000 g of k2CO3

2007-04-20 17:18:28 · 3 answers · asked by ♥y! answers_princess 2 in Science & Mathematics Chemistry

3 answers

Molecular mass K2CO3 = 138.2 g/mol

3.000 g/ 138.2 = 0.0217 mol K2CO3

The ratio between K2CO3 and KCl is 1 : 2 so we would get 2 x 0.0217 mol = 0.0434 mol KCl

Molecular mass KCl = 74.55 g/mol

Grams KCl = 74.55 x 0.0434 = 3.23

2007-04-20 17:26:33 · answer #1 · answered by Anonymous · 0 1

The mole of K2CO3=3/(39*2+12+16*3)=0.0217mol
From the fomula,we know 1 mole of k2co3 will produce
2 mole of kcl
So the mole of kcl formed =0.0217*2=0.0434mol
The mass of kcl formed=0.0434*(39+35.5)=3.2333g

2007-04-21 00:26:35 · answer #2 · answered by Anonymous · 0 0

Kristine, you need to follow the chemistry ladder:
grams to moles of reactant divide grams by mol weight of reactant
moles of product from moles of reactant.
Use the reaction formula.
mass of product multiply moles of reactant times its molecular weight.

There are the rungs, there are the formulas, you get the mol weights and figure it out for yourself.

2007-04-21 00:24:39 · answer #3 · answered by cattbarf 7 · 0 0

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