KOH(aq) + HNO3(aq) -->
2007-04-20 17:06:39 · 7 answers · asked by monique 2 in Science & Mathematics ➔ Chemistry
Thank You!!!
2007-04-20 17:26:41 · update #1
Potassium Nitrate
KNO3
KOH + HNO3 → H2O + KNO3
2007-04-20 17:11:25 · answer #1 · answered by Eric 6 · 0⤊ 0⤋
the different product is Strontium Iodide, SrI2. The Sr-OH and the two H-I bonds are broken on the left hand area. The O-H- ions integrate with the two H+ ions and style water (2H2O). The strontium ion then combines with iodide and varieties strontium iodide. confer with the stoichiometric equation under: Sr(OH)2(aq) + 2HI(aq) ----> 2H20(l) + SrI2(s)
2016-12-20 20:22:35 · answer #2 · answered by sheck 3 · 0⤊ 0⤋
Monique, you have to follow the bouncing ball on these questions. Your inputs break down into ions in water, K+, OH-, H+, and NO3-. If water is formed from H+ and OH-, the only other one left is K+ and NO3-. This is a "classic" acid-base reaction:
acid+base -> water + salt.
2007-04-20 17:13:14 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
KOH + HNO3 --> H2O + KNO3
2007-04-20 17:12:02 · answer #4 · answered by moneymonty 3 · 0⤊ 0⤋
KOH(aq) + HNO3(aq) --> H20 (l) + KNO3(s)
(PS: OH- + H --> H20)
2007-04-20 17:57:56 · answer #5 · answered by Kuan T 2 · 0⤊ 0⤋
KNO3(aq) + H2O(l)
2007-04-20 17:13:59 · answer #6 · answered by Yssa A 3 · 0⤊ 0⤋
potassium nitroxide KNO
2007-04-20 17:13:11 · answer #7 · answered by God 2 · 0⤊ 0⤋