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You have solutions of .2 M HNO(2) and .2 M KNO(2) (K(a) for HNO(2) = 4.00 x 10^-4) A buffer of pH 3 is needed. What volumes of HNO(2) and KNO(2) are required to make 1 liter of buffered solution?

numbers in ( ) are subscripts.

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2007-04-20 15:10:25 · 1 answers · asked by Zywiec 2 in Science & Mathematics Chemistry

1 answers

pH = pKa + log[Salt]/[Acid]

or log[Salt]/[Acid] = 3-3.398 = -0.398

or x/1-x = 0.4

or 1.4x = 0.4

or x = 285.7 ml of KNO2 soln and 1000-285.7 = 714.3 ml of HNO2 .

2007-04-20 18:36:54 · answer #1 · answered by ag_iitkgp 7 · 0 0

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