It's my Additional maths work. Please help me solve this problem. It looks simple but I can't get the answer.. (Please show the full solution) Thank you. :)
2007-04-20 13:26:55 · 6 answers · asked by Akakuro Sadame 1 in Science & Mathematics ➔ Mathematics
12^1/3 * 6^1/3 / 81^1/6 = (12 * 6)^1/3 / (9^1/3) = 72^(1/3) / 9^(1/3) = (72/9)^(1/3)=8^(1/3)=2
2007-04-20 13:33:24 · answer #1 · answered by - 1 · 0⤊ 0⤋
12 x 3 + 1 = 36 + 1 = 37, 6 x 3 + 1 = 18 + 1 =19, 81 x 6 + 1 = 486 + 1 = 487
37/3 x 19/3 x 487/6 = 342,361/54 = 6,340.02
2007-04-20 20:11:01 · answer #2 · answered by bootis32 6 · 0⤊ 0⤋
81^ 1/6 = 9^ 1/3, so you can rewrite the whole thing as (12*6/9)^ 1/3 = 8^ 1/3 =2
2007-04-20 13:41:02 · answer #3 · answered by jiyuztex 2 · 0⤊ 0⤋
Break the expression down to prime factors.
(12^1/3)(6^1/3) / (81^1/6)
= [(2²*3)^(1/3)][(2*3)^(1/3)] / [(3^4)^(1/6)]
= [(2³*3²)^(1/3)] / [(3²)^(1/3)]
= [(2³)^(1/3)]*[(3²/3²)^(1/3)] = 2*1 = 2
2007-04-20 14:28:05 · answer #4 · answered by Northstar 7 · 0⤊ 0⤋
Your formula is not showing proper mathematical symbols, there'e no ^ but if you meant X then you must mean;
12X1/3=4 12 divided by 3
6X1/3=2 6 divided by 3
81X1/6=13.5 81 divided by 6
4X2=8X13.5=108
2007-04-20 13:40:22 · answer #5 · answered by pjallittle 6 · 0⤊ 1⤋
Math problems are easier when you have a graphing calculator and your answerer is 2.
2007-04-20 13:38:31 · answer #6 · answered by disco girl 2 · 0⤊ 0⤋