I have a 65 in COAP (computer applications) class, and a 70 in a Math class. The passing grade is 60 percent. And the tests (finals) are both worth 60 percent each. What do I need to get on each test to pass?
In my English class, I need a 60 percent on the final to pass the class. The passing grade is 60 percent. That final is worth 50 percent of my mark. The question is: what is my mark, coming into the final?
2007-04-20 10:37:09 · 7 answers · asked by ? 6 in Science & Mathematics ➔ Mathematics
COAP:
you have 65*0.4=26 points so yo uneed 60-26=34 more points. Your grade on the hinal must be such that 0.6*g=34 or
g=34/0.6=57
Math
70*0.4=28 60-28=32 so
0.6*g=32
g=32/0.6=54
English
Since you need the same % on the final as the passing grade, you must have a 60 going in to the final. It doesn't even matter what % of your grade the final is.
2007-04-20 12:06:49 · answer #1 · answered by yupchagee 7 · 11⤊ 0⤋
Your current 65 is worth 65*.4=26 points of possible 40
So you need 60-26 = 34 more points to get 60
So .6x=34 --> x= 57 to pass COAP
You need 60-28= 32 to pass Math. So .6x=32 --> x = 54
You need 60*.5 = 30 out of possible 50 to pass
therefore you must have gotten 30 out of a possible 40 or 75% coming into the final.
2007-04-20 10:54:11 · answer #2 · answered by ironduke8159 7 · 0⤊ 1⤋
COAP: 2*60 - 65 = 55
Math: 2* 60 - 70 = 50
mark in English = 2* 60 - 60 = 60
2007-04-20 10:45:50 · answer #3 · answered by Jano 5 · 0⤊ 2⤋
COAP = 56 and 2/3
Math = 53 and 1/3
English = 60%
2007-04-20 10:43:10 · answer #4 · answered by Anonymous · 0⤊ 2⤋
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2016-10-28 14:00:46 · answer #5 · answered by Anonymous · 0⤊ 0⤋
65* 0.4 + x*0.6 = 60
x*0.6 = 34
x = 57 for passing grade in COAP
70*0.4+0.6x = 60
0.6x = 32
x = 54 for pass in math
passing grade is 60. you need 60 in final, so your existing mark has to be 60 as well.
2007-04-20 10:42:38 · answer #6 · answered by hustolemyname 6 · 0⤊ 2⤋
You should aim for a hundred.
But if you want to know, it's
COAP 57
Math 54
English 60
2007-04-20 10:43:33 · answer #7 · answered by MATHCOUNTS_awesome 3 · 0⤊ 1⤋