Grouping and all that...
I'm not entirely sure, but I think it's:
15x^3 y^4
2007-04-20 10:32:26
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answer #1
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answered by ? 4
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= (3 X 5) X (x² X x) X (y X y³)
= 15.x³.y^(4)
2007-04-20 21:31:06
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answer #2
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answered by Como 7
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NO! '^' does not mean 'squared'.It means 'to the power of'.
So the line of symbols you have written translates as:-(in english) 3 times(x squared) times y Multiplied by 5 times x times (y cubed).
THE ANSWER
3x^2yX5xy^3=3x5x^(2+1)Xy^(1+3)
=(in words) fifteen times xto the power 3 times y to the power 4.
remember! x^2=x timesx(can be written as x.x) and x^5=x.x.x.x.x.it follows(I think) that x^2 times x^5=x.x.x.x.x.x.x=x^(2+5)=x^7
2007-04-20 11:55:49
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answer #3
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answered by L D 6
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If ^2 is squared and ^3 is cubed
well first multiply the x's: 3x^2 x 5x. (add similar exponents together when you multiply) 15x cubed! Then y x y^3. That's y to the fourth power. So it's 15x^3y^4 (15xcubedytothefourth)
2007-04-20 10:35:59
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answer #4
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answered by ♥Lily♥ 2
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3x^2y X 5xy^3
= 15x^3y^4
In general x^m * x^n = x^(m+n).
So x^2 * x^1 = x^(2+1) = x^3
x^5 * x^12 = x^(5+12) = x^17
2007-04-20 10:36:16
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answer #5
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answered by ironduke8159 7
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(M^n)(N^m)= MN^n+m
(M^n)/(N^m)= MN^n-m
(M^n)^m= M^nm
(3x)^2y.(5xy)^3 =(15X^2.Y)^2Y+3
Fifteen x squared 2 multiplied by Y ; all that squared 2Y+3
2007-04-20 11:22:42
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answer #6
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answered by Mate. M 2
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(3x^2y)(5xy^3)
= 15(x^2y)(x)(y^3)
= 15[x^(2y+1)](y^3)
2007-04-21 04:04:10
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answer #7
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answered by Kemmy 6
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Ask your teacher for help!
The answer is 15x^3y^4.
2007-04-20 10:33:42
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answer #8
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answered by MATHCOUNTS_awesome 3
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I can't believe you are asking this, it's soooooooo obvious.
2007-04-20 10:48:25
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answer #9
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answered by Bum Gravy. 5
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sorry did it GCSE in yr 2000. see how useful it been to me lol :D haha, i cnat even wrk out % now in my head as i used to. i got an A by the way lol :D
2007-04-20 10:27:50
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answer #10
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answered by allgiggles1984 6
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