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13 answers

Grouping and all that...

I'm not entirely sure, but I think it's:

15x^3 y^4

2007-04-20 10:32:26 · answer #1 · answered by ? 4 · 0 1

= (3 X 5) X (x² X x) X (y X y³)
= 15.x³.y^(4)

2007-04-20 21:31:06 · answer #2 · answered by Como 7 · 0 0

NO! '^' does not mean 'squared'.It means 'to the power of'.
So the line of symbols you have written translates as:-(in english) 3 times(x squared) times y Multiplied by 5 times x times (y cubed).
THE ANSWER
3x^2yX5xy^3=3x5x^(2+1)Xy^(1+3)
=(in words) fifteen times xto the power 3 times y to the power 4.
remember! x^2=x timesx(can be written as x.x) and x^5=x.x.x.x.x.it follows(I think) that x^2 times x^5=x.x.x.x.x.x.x=x^(2+5)=x^7

2007-04-20 11:55:49 · answer #3 · answered by L D 6 · 0 0

If ^2 is squared and ^3 is cubed
well first multiply the x's: 3x^2 x 5x. (add similar exponents together when you multiply) 15x cubed! Then y x y^3. That's y to the fourth power. So it's 15x^3y^4 (15xcubedytothefourth)

2007-04-20 10:35:59 · answer #4 · answered by ♥Lily♥ 2 · 0 1

3x^2y X 5xy^3
= 15x^3y^4

In general x^m * x^n = x^(m+n).
So x^2 * x^1 = x^(2+1) = x^3
x^5 * x^12 = x^(5+12) = x^17

2007-04-20 10:36:16 · answer #5 · answered by ironduke8159 7 · 0 1

(M^n)(N^m)= MN^n+m
(M^n)/(N^m)= MN^n-m
(M^n)^m= M^nm


(3x)^2y.(5xy)^3 =(15X^2.Y)^2Y+3
Fifteen x squared 2 multiplied by Y ; all that squared 2Y+3

2007-04-20 11:22:42 · answer #6 · answered by Mate. M 2 · 0 0

(3x^2y)(5xy^3)
= 15(x^2y)(x)(y^3)
= 15[x^(2y+1)](y^3)

2007-04-21 04:04:10 · answer #7 · answered by Kemmy 6 · 0 0

Ask your teacher for help!
The answer is 15x^3y^4.

2007-04-20 10:33:42 · answer #8 · answered by MATHCOUNTS_awesome 3 · 1 0

I can't believe you are asking this, it's soooooooo obvious.

2007-04-20 10:48:25 · answer #9 · answered by Bum Gravy. 5 · 0 0

sorry did it GCSE in yr 2000. see how useful it been to me lol :D haha, i cnat even wrk out % now in my head as i used to. i got an A by the way lol :D

2007-04-20 10:27:50 · answer #10 · answered by allgiggles1984 6 · 0 3

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