1. What is the length of the arc intercepted on a circle of radius
14cms
>by the arms of a central angle of 45 degrees?
2007-04-20 09:14:24 · 5 answers · asked by K 4 in Science & Mathematics ➔ Mathematics
In order to use the formula you're quoting, your angle must be in radians, not degrees. So use π/4 in place of 45°. Then,
π/4 = L*14
L = 14π/4 = 7π/2 cm
2007-04-20 09:30:04 · answer #1 · answered by Kathleen K 7 · 0⤊ 0⤋
arc length = theta*radius if theta is in radians
45 degrees = Pi/4 radians
arc length = (Pi/4)14 = 11 cm
2007-04-20 16:45:47 · answer #2 · answered by bignose68 4 · 0⤊ 0⤋
arc length =radius x angle (in radians)
360 deg (one turn = 2pie radians
45 deg =pie/4 radians
arc length = 14 x pie/4 =10.995 cm say 11 cm
2007-04-20 16:26:16 · answer #3 · answered by Ronan C 2 · 0⤊ 0⤋
First: Put the central angle in radians:
45 degrees = 45 *Ï/180 radians = Ï/4
So s = rθ = 14Ï/4 = 7Ï/2 cm = 10.996 cm (approx.)
2007-04-20 18:07:11 · answer #4 · answered by steiner1745 7 · 0⤊ 0⤋
length of arc = theta/360 X 2X 22/7XR
= 45/360 X 2X22/7X14
= ans
OR
theta = lehgth / (360 X 2X 22/7XR)
this doesn't make any sense.
2007-04-20 16:37:25 · answer #5 · answered by harry m 6 · 0⤊ 1⤋