English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

When calcium is heated, a orange spectral line whose energy is 3.26 10-19 J per photon is produced.

(a) What is the frequency of this light?

(b) What is the wave length of this light?

2007-04-20 09:12:13 · 1 answers · asked by tim_childress 1 in Science & Mathematics Chemistry

1 answers

The basic formula is:

E = h * nu
or
E = h * (c / lambda)

E is the energy in Joules
h is plancks constant: 6.62606896 x 10^-34 Joule-seconds
nu (greek letter) is the frequency in Hz (cycles per second)
c is the speed of light: 3*10^8 meters/second
lambda is the wavelength in meters

3.26*10^-19 / 6.626*10^-34 = nu = 4.92*10^14 Hz

1 / (3.26*10^-19 / (6.626*10^-34 * 3*10^8) = 610 nm

more of a red than an orange, but the numbers should be right.
.

2007-04-20 09:16:31 · answer #1 · answered by tlbs101 7 · 0 0

fedest.com, questions and answers