2007-04-20 08:53:31 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Energy:
E = (Plank constant) x (frequency) =
= (Plank constant) x ((speed of light) / (wavelength))
Plank constant h = 4.135e-15 eV s
Speed of light c = 2.998e8 m/s
Wavelenght λ = 0.475e-6 m
Answer:
E = hc/λ = 2.61 eV
2007-04-20 09:37:26 · answer #1 · answered by Alexander 6 · 0⤊ 0⤋
E = h * c / lambda
h is Plancks constant, 6.626*10^-34 Joule-seconds
lambda is the wavelength: 475*10^-9 meters
c is the speed of light
E = 4.185*10^-19 Joules
2007-04-20 16:04:36 · answer #2 · answered by tlbs101 7 · 0⤊ 0⤋
E=hc/w
where E is energy
h=Plank's constant (value depends upon unit)
c=speed of light
w=wavelength
2007-04-20 16:05:39 · answer #3 · answered by Tim K 2 · 0⤊ 0⤋
photons dont have amplitude. They are discrete particles. Amplitude describes classical EM, not quantum EM which descrivbed photons and other things. E=hf=hc/lambda.
c=speed of light
h=planks constant
2007-04-20 16:47:52 · answer #4 · answered by rickpeet 3 · 0⤊ 0⤋
it depends on the amplitude...a red laser and red sunlite have the same wavelength but very diffrent amplitudes.
but this formular will help
E=h*f where f is the frequenzy and h is 6.626069*10^-34 js
2007-04-20 16:02:08 · answer #5 · answered by mareklspak 1 · 0⤊ 0⤋