im in a pre-calculus class and i have to complete the square for x^2+2x-y+3=0
2007-04-20 07:42:32 · 5 answers · asked by koala j 1 in Science & Mathematics ➔ Mathematics
y=x^2+2x+3
y-3=x^2+2x
y-3+1=x^2+2x+1
Y-2=(x+1)^2
y=(x+1)^2+2
2007-04-20 07:46:53 · answer #1 · answered by JO 3 · 0⤊ 1⤋
x² + 2x - y + 3 = 0
x² + 2x - y + 3 + y = 0 + y
x² + 2x + 3 = y
The left side of the equation
the middle term is + 2x
find the sum of the middle term
Multiply the first term 1 times the last term 3 equals 3 and factor
factors of 3 =
1 x 3. . .Use these factors
+ 3 and - 1 satisfy the sum of the middle term
1 = x
insert + 3x and - x into the eqution
x² + 2x + 3 = y
x² + 3x - x + 3 = y
x(x + 3) - 1(x + 3) = y
(x - 1)(x + 3)
- - - - - - - - -s-
2007-04-20 16:04:00 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
x^2 +2x-y +3=0
x^2 +2x= y-3
x^2 +(2x)/2 +(2/2) = y - 3+ (2/2)
x^2 +2x +1= y - 3 +1
(x +1)^2 = y- 2
y= (x+1)^2 + 2
2007-04-20 17:01:31 · answer #3 · answered by Anonymous · 0⤊ 0⤋
y = (x + 3)(x - 1)
2007-04-20 14:46:40 · answer #4 · answered by hotmail.stinks 1 · 0⤊ 1⤋
Go for it.
2007-04-20 14:46:05 · answer #5 · answered by Anonymous · 0⤊ 1⤋