x^2 + 49 = -14x
Rearrange into normal quadratic form
x^2 +14x +49 = 0
You want to factor into (x + a)(x+b)
You know both signs are plus because all parts of the quadratic are positive.
So you want to find a & b such that a*b = 49 and a+b = 14.
To find this, you can:
1) Plug it into the quadratic formula
2) Think & find the number directly
3) plot it and look for the zero crossings.
In this case it's easy since 7*7 = 49 and 7+7 = 14
So the factorization is (x + 7)(x+7)
2007-04-20 07:17:11
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answer #1
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answered by anotherbsdparent 5
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Bring everything over to one side
x^2 + 14x + 49 = 0
What are the factors of 14?
(1, 14) (2, 7)
Then you have to figure out combinations that will give you 49. The only thing here that divides into 49 is 7 and conveniently there are two of them. So you get:
(x + 7)(x + 7)
2007-04-20 07:16:26
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answer #2
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answered by sfpiano 4
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x^2 + 49 + 14 x = 0
Rearrange..
x^2 + 14x + 49
What times what=49..and the sum of those two factors adds up to 14?
(x+7)(x+7) = 0
(x+7)^2 = 0
x = -7
2007-04-20 07:14:26
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answer #3
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answered by RScott 3
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bring over to LHS
x^2 + 14x + 49 = 0
now I know that 49=7^2 and I see 14 = 2*7
(x+7)^2 = 0
so x = -7 is double root
2007-04-20 07:16:34
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answer #4
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answered by hustolemyname 6
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x^2+14x+49=0 (x+7)^2
2007-04-20 07:14:58
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answer #5
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answered by dwinbaycity 5
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x^2 + 49 = -14x
x^2 + 14x + 49
(x + 7)^2
2007-04-20 11:42:10
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answer #6
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answered by Sherman81 6
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x^2 + 49 = -14x
x^2+14x+49 = 0
(x + ?)(x+?) =0
The ?'s must be two numbers which when added = 14 and when multiplied = 49.
Obviously the ?'s are both 7, so we have
(x+7)(x+7) = (x+7)^2
2007-04-20 07:18:42
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answer #7
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answered by ironduke8159 7
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Make the whole equation on one side...so its x^2 + 14x + 49 = 0
Now...this is kindve a guess and check thing that you get better and better at.
Just by looking at this I knew it was
(x + 7)(x + 7)
You need to know that the numbers (7) need to add up to 14, and multiply to 49...7 is the obvious choice.
2007-04-20 07:13:21
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answer #8
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answered by Anonymous
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x^2 + 49 = -14x
x^2 + 14x + 49 = 0
(x + 7)(x + 7) = 0
The whole concept of factoring can be thought of like the reverse of the FOIL method. You want to find two factors that, when multiplied together completely, comes out like your original polynomial. Unfortunately, though, it requires a lot of trial and error, and I can't say there is any clear-cut, step-by-step way to factor polynomials.
The trick, though, is to look at the final constant, which in this case is 49, and try to list its factors (whether on paper or with practice in your head). At the same time, you also have to look at the coefficient of the middle term, which turns out to be 14 once I rearranged the terms, and figure out which of the factors of 49, when multiplied in the order of FOIL, will also give you 14. The way to do that is to consider the signs. In this case you have all positive signs separating the terms, so you know that within your factors you'll be adding. By working them out one at a time and trying to figure out which one works, you should find that 7, when added (7x + 7x), gives you your middle term, and when multiplied gives you your constant.
Like I said, there's is no definite way to reverse FOIL, but with practice it gets easier.
2007-04-20 07:21:39
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answer #9
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answered by skm4usa 3
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a million) 2x^5 + 3x^4 – 4x^2 x^2(2x^3 + 3x^2 - 4) 2) xy + 7y – 3x – 21 element a y from the 1st 2 words and a -3 from the 2d 2 words y(x + 7) -3(x + 7) Now element (x + 7) from the two words (x + 7)(y - 3) 3) 10x^2 – 23xy +12y^2 (2x - 3y)(5x - 4y) See the lesson on the link decrease than 4) y^2 – 40 9 (y + 7)(y - 7) {distinction of two squares} you're able to get this effect once you factored the trinomial y^2 + 0x - 40 9 5) a million – 125y^3 Did you propose -125y^2? 6) x2 + 14x + 40 9 (x + 7)^2
2016-11-26 00:44:50
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answer #10
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answered by ? 4
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