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compare dy and deltay for y=-4x^4+1 at x=0 with dx=0.?

2007-04-20 06:37:21 · 1 answers · asked by markusa_j 1 in Science & Mathematics ➔ Mathematics

1 answers

dy = -16x^3dx
∆y = (- 4x^4 + 1 - 0 - 1) = - 4x^4
at x = 0 and dx = 0 both are 0

2007-04-20 07:02:35 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋

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