multiplying trinomial fractions?

Question

[n^2-n-20/2n^2] * [n^2 + 5n/n^2-25]

Need Help... please help... show work. Thank you all in advance.

Answer 1

Yuch..What a pain in the ****..LOL..But here is how, sir.

Multiply each term in the first expression, but each term in the second expression...so on down the line...

n^2(n^2 + 5n/n^2 - 25)
-from here on simplify the linear term 5n/n^2 to 5/n

Do that for every term

-n(n^2 + 5/n - 25)

So on down the line

Once you have done this simply remove all parenthesis and add the terms...

Aye yie yie..I get a headache just looking at it..But that is how you do it..

I will leave the actual work for you to do

Please remember..If this problem makes you gag, it's natural..This one is a pain, it just a matter of taking you time and making sure you get your signs right..

Answer 2

This is a simplification problem when you factor you find:
n^2 - n -20 = n-5 times n+4
and:
n^2 - 25 = n-5 times n + 5
multiply the numerators
(n-5) (n+4) (n) ( n +5)
multiply the denominators
(2) (n) (n) (n+5) (n-5)
Eliminate the equivalent terms (n) (n-5) (n+5) which appear in both the numerator and denominator.
leaving
(n+4) / 2 n

Answer 3

(n-5)(n+4)/2n^2 * n^2+5n/n^2-25

(n-5)(n+4) n(n+5)
----------------------------------------
2n^2 (n-5)(n+5)

the 2 n+5 and n-5 cancel out

n(n+4)/2n^2 and cancel out the n

answer n+4/2n