in radians
2007-04-20 06:11:03 · 4 answers · asked by jogger 1 in Science & Mathematics ➔ Mathematics
Note that sin(x) = y , arcsin(y) = x
so you have arcsin(sin(x)) = arcsin(y)=x
so your answer is
3pi/2
2007-04-20 06:18:57 · answer #1 · answered by mangaFan 2 · 0⤊ 2⤋
Correct me if I'm wrong but doesn't the arcsin and sin cancel out? Therfore your answer is 3pi/2.
I think poster above had it confused for cos(sin instead of arcsin (sin)
2007-04-20 06:18:16 · answer #2 · answered by Anonymous · 1⤊ 1⤋
hi
First
3 pi /2 + 2 k' pi
= (4k' + 3) pi /2
= (4k + 1) pi/2
Second
(pi - 3 pi /2) + 2 k pi
= (4k - 1) pi/2
then
solution: = (4k +/- 1) pi/2
bye
2007-04-20 09:28:02 · answer #3 · answered by railrule 7 · 0⤊ 0⤋
= - 1.570796327
= -pi/2
2007-04-20 06:17:56 · answer #4 · answered by ironduke8159 7 · 0⤊ 1⤋