Are the following lines parallel, perpindicular, or neither?

Question

L1 with the equation x- 2y = 10 L2 with equation 2x + y = 2

Answer 1

-2y = 10 - x
2y = x - 10
y = x/2 - 5 { Slope = 1/2 }

y = -2x + 2 { Slope = -2 }

The two lines have negative-reciprocal slopes, so they are perpendicular

Answer 2

In order to answer your question you must determine the slopes of the lines...Remember these rules:

1.) If the slopes are EQUAL..The lines are Parallel

2.) IF the Slopes are negative reciprocals, the lines are perpendicular.

In your problem we have two lines that we must get into standard form y=mX+b
x- 2y = 10
-2y=-x-10..Divide through by a negative one to get rid of the negative on the Y value
2y=x+10
y=1/2x + 5..Our slope is 1/2 on this one

2X+y=2
y=-2X+2 The slope is 2

We have -1/2 and 2..These are in fact NEGATIVE RECIPROCALS of one another..Which indicates that these lines are perpendicular to one another.

Hope this helps you

Answer 3

L1: x - 2y = 10
-2y = -x - 10
y = (1/2)x + 5
L2: 2x + y = 2
y = -2x + 2

Slopes are opposite reciprocals, so the answer is perpendicular.

Answer 4

These lines are perpendicular:
Solve each for y:
L1: 2y = x-10
y = ½x -5. Slope ½.

L2: y -2x+2 Slope -2.
Since ½ and -2 are negative reciprocals,
the lines are perpendicular.

Answer 5

Solve each for y & compare the coefficients of x, which is the slope:
L1:
x - 2y = 10
-2y = -x + 10
y = (1/2)x - 5
L2:
2x + y = 2
y = -2x + 2
Since, (1/2)(-2) = -1, the lines are perpendicular.

Answer 6

Slope L1 = 1/2
Slope L2 = -2
Since the product of the slopes is -1, the lines are perpendicular.

Answer 7

x-3y=9 -3y=-x+9 y=x/3 +3 3x+y=3 y=-3x+3 the slope of both lines are the reciprocal of one yet another, for this reason those lines are perpendicular. to research you are able to continuously plug it in a graph. in basic terms endure in options that went conversing about slope y=mx+b in parallel lines the mx [slope] continues to be an same, despite the indisputable fact that in perpendicular is expressed because the unfavorable reciprocal. desire this helped =]

Answer 8

put both into point slope form: y = mx + b

y = x/2 -5 and y = -2x +2

the slope (m) of the first is 1/2 and the second is -2

They are not parallel because the slopes are not equal
They are perpendicualar because the slopes are negative reciprocals of each other

Answer 9

you need to consider the gradients

L1 x-2y=10

2y= x-10

y= x/2 - 5

gr = 1/2

L2 2x + y = 2

y=-2x + 2

gr = -2

If two lines are perpendicular then the product of their gradients is -1.

In this case

1/2 * -2 = -1

so the lines are perpendicular

Answer 10

x-2y=10 ---> y=1/2x -5
m=1/2

2x+y=2 ---> y=-2x+2
m=-2

since their slopes are negative reciprocals, it is perpendicular