[x/5x+10] + [x-3/x+2] = 7/5
Need help. i don't understand this. Please show me the work.
2007-04-20 05:31:58 · 3 answers · asked by Jazzy J 1 in Science & Mathematics ➔ Mathematics
[x/5(x+2)] + [(x-3)/(x+2)] = 7/5
multiply both sides by 5(x+2) to cancel out the denominator
x + 5(x-3) = 7(x+2)
x + 5x - 15 = 7x + 14
6x -7x = 14 + 15
-x = 29
x = -29
2007-04-20 05:42:14 · answer #1 · answered by Fwapi 2 · 0⤊ 1⤋
[x/5x+10] + [x-3/x+2] = 7/5
I assume you mean:
x/(5x+10) + (x-3)/(x+2) = 7/5
x/(5(x+2)) + 5(x-3)/(5(x+2)) = 7(x+2)/(5(x+2))
Now that all the denominators are the same, we can simply equate the numerators as follows:
x+5(x-3)=7(x+2)
x+5x-15=7x+14
6x-15 = 7x +14
-29 =x
2007-04-20 05:55:31 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
It depends on exactly what you're refering to.
if you mean:
[x/(5x+10)]+[(x-3)/(x+2)] = 7/5
then the answer is x = -29
Procedure:
Multiply by 5x+10, you get
x + 5(x-3) = 7(x+2)
then:
x+5x-15=7x+14
6x-15=7x+14
-x=29
x=-29
2007-04-20 05:43:46 · answer #3 · answered by rfmarves 2 · 0⤊ 0⤋