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i need help solving this quadratic equation.
x^4 - x^2 - 4 = 0

2007-04-20 04:17:40 · 4 answers · asked by 12345 2 in Education & Reference Homework Help

4 answers

X^4 - X^2 - 4=0
x^2 - X - 2 = 0 (square root the whole equation)
(x + 1) (x - 2) = 0

thus, x = -1 , x = 2

2007-04-20 04:28:15 · answer #1 · answered by gwennie 3 · 0 2

This is actually a quartic equation. It will have 4 roots.
It is quadratic in x². So let u = x² and we must solve
u² - u -4 = 0.
Since b²-4ac is 17, we cannot solve this by factoring,
so let's use the quadratic formula:
We get u = ½(1 + √17)
or u = ½(1 - √17).
Then the 4 roots of the original equation are
x = √ ½(1 + √17)
x = -√ ½(1 + √17)
x = √ ½(1 - √17)
x = -√ ½(1 - √17).
Hope that helps!

2007-04-20 12:11:28 · answer #2 · answered by steiner1745 7 · 0 0

x^4 - x^2 - 4 = 0
(x^2 - 2)(x^2 +2)=0
x^2 -2 =0 x^2+2=0
x^2=2 x^2= -2
x= square root 2 or 2^(1/2) x= not vaild b/c it is the square root of -2.

x= 2^(1/2) or sqaure root 2

2007-04-20 11:28:57 · answer #3 · answered by tenniscolleggrl24 2 · 1 2

x = 1.6

2007-04-20 11:31:13 · answer #4 · answered by shaheer 2 · 0 1

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