x+3 = square root of 16x
(squaring both the sides)
therefore, (x+3)^2= 16x
x^2 + 9 + 6x = 16
x^2 - 10x + 9 = 0
(x^2 -9x) - (x-9) = 0
(x-9)(x-1) = 0
therefore, x = 9 or 1
2007-04-20 04:58:42
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answer #1
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answered by absentmindednik 3
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X=1
2007-04-20 04:01:40
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answer #2
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answered by Anonymous
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x=1
2007-04-20 04:05:55
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answer #3
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answered by Emma Chica 3
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[Your question has a typo by the way. It should be x+3= the square root of 16]
x + 3 = square root of 16
x + 3 = 4 >>>> (square root of 16 is 4)
x = 4 - 3 >>>> (now bring over the 3 to the other side. when you bring any number over the sign changes >> + becomes - in this case)
x = 1 (Answer)
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In computer-language square root is typed out as v
Hence, the square root of 16x is typed as v16.
2007-04-20 04:08:00
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answer #4
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answered by in 30mins 3
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x + 3= square root of 16
square of x+3= square of square root of 16
x squared + 6x + 9= 16x
(we need to square both sides: x= 3 & sq. root of 16 to eliminate the square root sign.)
now, we need to get the x by factoring the polynomial we got, which is x squared + 6x - 16x + 9= 16x-16x, to eliminate 16x to the right side.
then, it will be x sq. - 10x + 9=0
factor it so it will be...
x= 9; x=1
this is how we got it:
x-9
x-1
______________
x^2 -9x
- x + 9
_______________
x^2- 10 + 9
** x^2 means x squared
2007-04-20 04:19:21
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answer #5
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answered by Ninik 3
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x + 3 = sqrt(16x)
(x + 3)² = 16x
x² + 6x + 9 - 16x = 0
x² - 10x + 9 = 0
(x - 9)(x - 1) = 0
x = 1 or x = 9
2007-04-20 04:05:01
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answer #6
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answered by Dave 6
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ok, set x^2 -16x = -3 Now to make a suited sq. out of the LHS you're able to could desire to upload sixty 4 to it to offer (x-8)^2. yet you're able to desire to upload sixty 4 to the RHS and that could desire to finally end up with 61. so which you have (x-8)^2 = 61. Take sq. roots of the two factors and upload 8 to the two factors and undergo in suggestions you will choose 2 solutions.
2016-11-26 00:23:43
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answer #7
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answered by Anonymous
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x+3 =sqrt16x
square both sides of equation
x^2 +6x +9 = 16x
collect terms
x^2 -10x +9 = 0
factor
(x -1)(x-9) = 0
x=1
x=9
2007-04-20 04:09:43
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answer #8
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answered by bignose68 4
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you square the two sides
(x+3)^2= 16x
x^2+6x+9 =16x
x^2-10x +9 =0
x=1 and x=9
you can check .it works!
2007-04-20 04:13:40
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answer #9
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answered by maussy 7
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(x + 3)² = 16x
x² + 6x + 9 = 16x
x² - 10x + 9 = 0
(x - 9).(x - 1) = 0
x = 9 , x = 1
2007-04-20 04:14:17
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answer #10
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answered by Gagan 2
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