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what is x equal to?

2007-04-20 03:58:38 · 16 answers · asked by Lillpill 2 in Science & Mathematics Mathematics

16 answers

x+3 = square root of 16x
(squaring both the sides)
therefore, (x+3)^2= 16x
x^2 + 9 + 6x = 16
x^2 - 10x + 9 = 0
(x^2 -9x) - (x-9) = 0
(x-9)(x-1) = 0

therefore, x = 9 or 1

2007-04-20 04:58:42 · answer #1 · answered by absentmindednik 3 · 0 0

X=1

2007-04-20 04:01:40 · answer #2 · answered by Anonymous · 0 1

x=1

2007-04-20 04:05:55 · answer #3 · answered by Emma Chica 3 · 0 0

[Your question has a typo by the way. It should be x+3= the square root of 16]

x + 3 = square root of 16

x + 3 = 4 >>>> (square root of 16 is 4)

x = 4 - 3 >>>> (now bring over the 3 to the other side. when you bring any number over the sign changes >> + becomes - in this case)

x = 1 (Answer)

------------------

In computer-language square root is typed out as v
Hence, the square root of 16x is typed as v16.

2007-04-20 04:08:00 · answer #4 · answered by in 30mins 3 · 0 0

x + 3= square root of 16

square of x+3= square of square root of 16
x squared + 6x + 9= 16x
(we need to square both sides: x= 3 & sq. root of 16 to eliminate the square root sign.)
now, we need to get the x by factoring the polynomial we got, which is x squared + 6x - 16x + 9= 16x-16x, to eliminate 16x to the right side.

then, it will be x sq. - 10x + 9=0
factor it so it will be...
x= 9; x=1

this is how we got it:
x-9
x-1
______________
x^2 -9x
- x + 9
_______________
x^2- 10 + 9

** x^2 means x squared

2007-04-20 04:19:21 · answer #5 · answered by Ninik 3 · 0 0

x + 3 = sqrt(16x)
(x + 3)² = 16x
x² + 6x + 9 - 16x = 0
x² - 10x + 9 = 0
(x - 9)(x - 1) = 0
x = 1 or x = 9

2007-04-20 04:05:01 · answer #6 · answered by Dave 6 · 1 0

ok, set x^2 -16x = -3 Now to make a suited sq. out of the LHS you're able to could desire to upload sixty 4 to it to offer (x-8)^2. yet you're able to desire to upload sixty 4 to the RHS and that could desire to finally end up with 61. so which you have (x-8)^2 = 61. Take sq. roots of the two factors and upload 8 to the two factors and undergo in suggestions you will choose 2 solutions.

2016-11-26 00:23:43 · answer #7 · answered by Anonymous · 0 0

x+3 =sqrt16x
square both sides of equation
x^2 +6x +9 = 16x

collect terms
x^2 -10x +9 = 0

factor
(x -1)(x-9) = 0
x=1
x=9

2007-04-20 04:09:43 · answer #8 · answered by bignose68 4 · 0 0

you square the two sides

(x+3)^2= 16x

x^2+6x+9 =16x

x^2-10x +9 =0

x=1 and x=9

you can check .it works!

2007-04-20 04:13:40 · answer #9 · answered by maussy 7 · 0 0

(x + 3)² = 16x
x² + 6x + 9 = 16x
x² - 10x + 9 = 0
(x - 9).(x - 1) = 0
x = 9 , x = 1

2007-04-20 04:14:17 · answer #10 · answered by Gagan 2 · 0 0

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