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2007-04-18 22:48:41 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

1/2 sec^2( t)

I am assuming that you are looking for derivative with respect to t.

2007-04-18 22:51:25 · answer #1 · answered by Anonymous · 0 0

The derivative of Tan t is sec^2t
So
dy/dt=1/2sec^2t

2007-04-19 06:25:11 · answer #2 · answered by Nicholas 3 · 0 0

y = 1/2 tan t
y' = (1/2) sec^2t.

or
1/2cos^2t

2007-04-19 07:01:17 · answer #3 · answered by Rose 2 · 0 0

Assume you mean:-
y = (1/2).tan t
dy/dt =(1/2).sec² t

2007-04-19 05:57:30 · answer #4 · answered by Como 7 · 0 0

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