A five digit number is formed using digits 1,3,5,7 and 9 without repeating any one of them. What is the sum of all such possible numbers?
2007-04-18 22:02:33 · 6 answers · asked by chekku jane 1 in Science & Mathematics ➔ Mathematics
You have total of 5*4*3*2*1 = 120 such numbers.
1 3 5 7 9
1 3 5 9 7
1 3 7 5 9
1 3 7 9 5
1 3 9 5 7
1 3 9 7 5
etc.
On every position you will have 24 times each number (120 /5, obviously, each of them has equal frequency).
So the summ will be 11111* 24* (1+3+5+7+9) = 24*25*11111 = 6666600.
2007-04-18 22:24:29 · answer #1 · answered by --sv-- 2 · 0⤊ 0⤋
There are 152 ways to arrange a 5 digit no. without repeating:
5!+4!+3!+2!+1!
152 * 25 ( = sum of 1+3+5+7+9) = 3800
2007-04-19 05:23:51 · answer #2 · answered by funme 2 · 0⤊ 0⤋
120 Numbers
2007-04-19 05:22:29 · answer #3 · answered by ram s 2 · 0⤊ 0⤋
THE SUM is a long number.
Not interesting question!
If you have time, try to find the result by yourself.
2007-04-19 05:32:19 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋
20 i think.ü i really did not understand the question but if you mean how many different numbers can you form from those numbers, then 20 might just be the answer.ü
2007-04-19 05:11:20 · answer #5 · answered by hellofriend! 3 · 0⤊ 0⤋
6666600
Basically, all numbers shall appear 24 times in all positions..
2007-04-19 05:22:52 · answer #6 · answered by Me & Myself 2 · 0⤊ 0⤋