need to know how to do this step by step, so that I will be able to solve other problems like this.
(3t - 2) (2t + 3)
It says to find the product.
2007-04-18 19:24:44 · 10 answers · asked by cougarhw 1 in Science & Mathematics ➔ Mathematics
=(3t-2)(2t+3)
=6t^2+9t-4t-6
=6t^2+5t-6
-6t^2-5t=-6
-1[-6t^2-5t=-6]-1
6t^2+5t=6
2007-04-18 19:39:53 · answer #1 · answered by eLektra513 3 · 0⤊ 0⤋
Ans: 6t^2 +5t - 6
Working:
3t x 2t = 6t^2
3t x 3 = 9t
-2 x 2t = -4t
-2 x 3 = -6
6t^2 + 9t - 4t - 6=
6t^2 +5t - 6
2007-04-19 02:38:21 · answer #2 · answered by Asia 4 · 0⤊ 0⤋
Find the product means that you have to multiply by 3t and then by - 2:-
6t² + 9t - 4t - 6 = 6t² + 5t - 6
2007-04-19 03:19:22 · answer #3 · answered by Como 7 · 0⤊ 0⤋
use the FOIL method
multiply the first two >>>>> 3t x 2t
multiply the outside two>>> 3t x 3
multiply the inside two>>>>-2 x 2t
multiply the last two>>>>> 2 x 3
you would then get:
6t squared + 9t - 4t + 6
add them up
6t squared + 5t + 6
2007-04-19 02:31:51 · answer #4 · answered by SlamDUNK 4 · 0⤊ 0⤋
(3t - 2) (2t + 3)
=3t(2t + 3) - 2(2t +3)
=6t^2 + 9t - 4t -6
=6t^2 + 5t -6
2007-04-19 03:22:32 · answer #5 · answered by rizz_boss 1 · 0⤊ 0⤋
(3t - 2) (2t + 3)
=3t*2t +3t*3 -2*2t -2*3
=6t^2 +9t -4t -6
=6t^2 +5t -6
2007-04-19 02:30:05 · answer #6 · answered by ironduke8159 7 · 0⤊ 0⤋
(3t-2)(2t+3)
first mulitply the first number in the first bracket with the numbers in the second
6t+9t
next multiply the second number in the first bracket with the numbers in the sicond bracket.
6t+9t-4t-3= 11t-3
2007-04-19 02:57:11 · answer #7 · answered by DJ 2 · 0⤊ 0⤋
Multiply the two terms in the left parenthesis by the two terms in the right one. Then add.
6tt
9t
-4t
-6
Added together it is:
6tt + 5t - 6
2007-04-19 02:30:25 · answer #8 · answered by Mark 6 · 0⤊ 0⤋
(3t-2)(2t+3)
=>6t2+9t-4t-6
=>6t2+5t-6
2007-04-19 02:30:20 · answer #9 · answered by sania i 2 · 0⤊ 0⤋
6t^2-4t+9t-6
6t^2+5t-6
2007-04-19 02:39:20 · answer #10 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋