I've got a complicated Chemistry problem here, can anyone solve it?

Question

Ok, here it is:

A solution of CaF2 has [Ca++] = 3.1 x 10^-4 and [F-] = 1.5 x 10^-3. If PbI2 has Ksp = 3.9 x 10^-11, then will a precipitate form in the solution?

I know that it sounds like that's not all to the question, but it is. This one truly has me stumped. Does anyone know the answer?

Answer 1

The question is incomplete, the conc of CaF2 will have no effect on PbI2.

Answer 2

yes. check your solubility guide lines and you'll see that PbXy, where X=halogen and y is the charge of Pb, PbXy is actually insoluble and will therefore form a precipitate. it's a trick question.