Find the corresponding rectangular equation by eliminating the parameter: x = 2 + secθ ; y = 1 + tanθ.?

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Find the corresponding rectangular equation by eliminating the parameter: x = 2 + secθ ; y = 1 + tanθ.?

2007-04-18 16:40:12 · 2 answers · asked by helpmewithphysics 1 in Science & Mathematics ➔ Mathematics

2 answers

We know sec^2 θ = 1 + tan^2θ.
So (x-2)^2 = 1 + (y-1)^2
<=> x^2 - 4x + 4 = y^2 - 2y + 2
<=> x^2 - 4x - y^2 + 2y + 2 = 0.

2007-04-18 16:44:56 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 0⤋

we know that sec^2 T =1 + tan^2 T

from equations
x=2 + secT ===> secT = x-2
y = 1+tanT ====>tanT = y-1

(x-2)^2 = 1 + (y-1)^2

(x-2)^2 - (y-1)^2 = 1

:)

2007-04-18 23:45:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋