In stoichiometry if 1.25 g of copper is heated with an excess of sulfur, how many grams of sulfur will react?

Question

formula: Cu(s) + S(s) ---> CuS(s) must show work stoichiometry

Answer 1

Cu + S ----> CuS

One mole of Cu reacts with one mole of S to form one mole of CuS.

So Copper reactivity ratio with S is (1:1)

First work out the number of moles of Cu

No. of moles of Cu = weight of Copper / molecular mass of Cu

Wait you going to have to do some of the work or you will never learn.

No as you know one mole of Cu reacts with one mole of S
you can work out the number of moles of S.

No of moles S reacted = No. of moles of Cu x 1.

Now convert back into weight/

Weight of S reacted = No. of moles of S x molecular mass of S

Answer 2

63.5 g of Cu reacts with 32 g of S

So, 1.25 g of Cu will react with 1.25*32/63.5 g = 0.63 g of S

Answer 3

moles copper = moles sulfur

g Cu/atomic wt = g S / atomic wt

g S = g Cu x atomic wt S / atomic wt Cu

Answer 4

the problem cannot be solved because there is only one given mass.