2007-04-18 16:16:07 · 5 answers · asked by slashrocks25 2 in Science & Mathematics ➔ Mathematics
please explain
2007-04-18 16:16:38 · update #1
I can help u with this. U can't have i in the denominator right? well u can multiply the fraction u have with a conjugate number to get rid of i in the denominator
1. 2/(3+i)
(2/(3+i))(3-i/3-i) ------ the (3-i)/(3-i) is equal to one
(6 - 2i)/(9-i^2)
(6-2i)/(9--1)
(6-2i)/10 = (3-i)/5
2007-04-18 16:23:43 · answer #1 · answered by bob b 3 · 0⤊ 0⤋
To rationalise 2/(3+i) multiply numerator and denominator
by 3-i. You get
2(3-i)/10 = (3-i)/5.
2007-04-18 23:36:06 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋
2/(3+i)
=2 x (3-i) /( 3^2 + 1^2)
=(6 - 2i) / 10
=3/5 - i/5
2007-04-18 23:19:35 · answer #3 · answered by tanyeesern 2 · 0⤊ 0⤋
(3-i)/2
2007-04-18 23:19:47 · answer #4 · answered by sanjana 2 · 0⤊ 1⤋
0.632 angle -18.43
or
.6 -.2i
2007-04-18 23:19:19 · answer #5 · answered by CRAZYDEADMOTH 3 · 0⤊ 0⤋