(3x+5)^2+(4x - 12)^2=(5x+13)^2
and explain please!!!!! thank you so much!
2007-04-18 15:51:42 · 4 answers · asked by rt1290 6 in Science & Mathematics ➔ Mathematics
Foil each parenthesis
(9x^2+30x+25)+(16x^2-96x+144)
=25x^2+130x+169
Combine like terms
25x^2-66x+169=25x^2+130x+169
Subtract 25x^2 from both sides
-66x+169=130x+169
Subtract 169 from both sides
-66x=130x
Add 66x to both sides
0=196x
Divide both sides by 196
So we get x=0 and this is our only answer.
2007-04-18 16:02:50 · answer #1 · answered by Jim 5 · 0⤊ 0⤋
(3x + 5)^2 + (4x - 12)^2 = (5x + 13)^2
((3x + 5)(3x + 5)) + ((4x - 12)(4x - 12)) = (5x + 13)(5x + 13)
(9x^2 + 15x + 15x + 25) + (16x^2 - 48x - 48x + 144) = 25x^2 + 65x + 65x + 169
9x^2 + 30x + 25 + 16x^2 - 96x + 144 = 25x^2 + 130x + 169
25x^2 - 66x + 169 = 25x^2 + 130x + 169
-66x = 130x
x = 0
Unless you wrote something wrong, the answer is x = 0
2007-04-18 23:01:40 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋
(3x+5)(3x+5) + (4x-12)(4x-12) = (5x+13)(5x+13)
(9x^2 + 30x + 25) + (16x^2 - 96x + 144) = 25x^2 + 130x + 169
25x^2 - 66x + 169 = 25x^2 + 130x + 169
(25x^2 - 66x + 169) - (25x^2 + 130x + 169) =
(25x^2 + 130x + 169) - (25x^2 + 130x + 169)
-196x = 0
2007-04-18 23:02:44 · answer #3 · answered by canderson85635 2 · 0⤊ 0⤋
This looks like a trick question. x=0 is a solution. Check out a 5-12-13 right triangle.
2007-04-18 23:03:25 · answer #4 · answered by cattbarf 7 · 0⤊ 0⤋