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Does anyone know who to express log √(x^4 / yz) in terms of sums and differences of logarithms

2007-04-18 15:10:46 · 3 answers · asked by TICKLES 1 in Science & Mathematics Mathematics

3 answers

First it would be(1/2)log(x^4/yz)=(1/2)[4log(x)-log(y)-log(z)]

2007-04-18 15:15:09 · answer #1 · answered by bruinfan 7 · 0 1

log a - log b = log (a/b) log√( x^4 / yz) = log ( √(x^4) / √(yz) = log √(x^4) - log √(yz) = log x^2 - log√( yz) = log x^2 - 1/2log(yz)

2016-05-18 03:55:00 · answer #2 · answered by ? 3 · 0 0

log(sqrt(x^4/(yz)))
log((x^4/(yz))^(1/2))
(1/2)log((x^4)/(yz))
(1/2)(log(x^4) - log(yz))
(1/2)(log(x^4) - (log(y) + log(z)))
(1/2)(log(x^4) - log(y) - log(z)
(1/2)log(x^4) - (1/2)log(y) - (1/2)log(z)
2log(x) - (1/2)log(y) - (1/2)log(z)

2007-04-18 15:15:54 · answer #3 · answered by Sherman81 6 · 1 0

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