2007-04-18 15:07:37 · 6 answers · asked by Alex 2 in Science & Mathematics ➔ Mathematics
Take the natural log of both sides: x=(x+2)ln(3)
so x-xln(3)=2ln(3)
or x(1-ln(3))=2ln(3)
so x=2ln(3)/(1-ln(3))
2007-04-18 15:13:26 · answer #1 · answered by bruinfan 7 · 1⤊ 0⤋
I don't know if this has a solution, since e^x<3^x for any positive value of x, and for negative values, you only go between 0 and 1.
2007-04-18 22:12:19 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
Hey, can I recommend taking the natural log on both sides. So...
e^x=3^x+2
x ln e = x ln3 +2
I can take you that far but I am not sure what comes next. Hope this helps. If you figure out tell.
2007-04-18 22:15:27 · answer #3 · answered by aurora 2 · 0⤊ 1⤋
e^x = 3^(x + 2)
xln(e) = (x + 2)ln(3)
x = xln(3) + 2ln(3)
x - xln(3) = 2ln(3)
x(1 - ln(3)) = 2ln(3)
x = (2ln(3))/(1 - ln(3))
2007-04-18 22:18:00 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
what are you solving for, e or x?
2007-04-18 22:11:17 · answer #5 · answered by mc_bbchs_2010 3 · 0⤊ 1⤋
kid, look it up on google
2007-04-18 22:10:21 · answer #6 · answered by *Hawaian_Chic_101* 4 · 0⤊ 1⤋