homework help
2007-04-18 14:03:03 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
First: express each value in lowest terms.
1) 2*5 = 10
2) 2*2*3 = 12
3) 2*2*2*2 = 16
SEc: find the smallest multiple from each list...2
2007-04-18 14:20:50 · answer #1 · answered by ♪♥Annie♥♪ 6 · 3⤊ 2⤋
2^4 * 3 * 5 = 16 * 15 = 240
Figure out the prime factors of each, and get the union of the sets - 16 is 2 to the fourth power, so it must have 2^4. Twelve has a two, but you already have those, so you take the 3, and take the 5 from 10.
Multiply them together.
2007-04-18 21:09:31 · answer #2 · answered by John T 6 · 0⤊ 1⤋
The prime factors of these numbers are (2,5), (2,2,4) and (2,2,2,2). So the smallest set of prime factors that we can make any of these numbers from is (2,2,2,2, 4, 5). So the least common mulitple (the lowest number that's a multiple of all three) is 2*2*2*2*4*5 = 8*2*20 = 8*40 = 320.
2007-04-18 21:21:01 · answer #3 · answered by Anonymous · 0⤊ 1⤋
240
2007-04-18 21:10:26 · answer #4 · answered by joe 3 · 0⤊ 0⤋
The answer is 240.
Find the largest number that divides into all three numbers. Two. Divide each number by the number (two). Multiply the results: 5x6x8 Answer: 240
2007-04-18 21:11:08 · answer #5 · answered by LUELLA T 1 · 0⤊ 0⤋
2
2*5=10
2*6=12
2*8=16
2007-04-18 21:06:25 · answer #6 · answered by JB 2 · 0⤊ 2⤋
2. Bc 2 goes into 10, 12, and 16 evenly and the least amount of times bc your looking for the LCM
2007-04-18 21:10:45 · answer #7 · answered by Anonymous · 0⤊ 1⤋
480
2007-04-18 21:07:50 · answer #8 · answered by Ninja_of_heroes 2 · 0⤊ 3⤋
10 = 2(5)
12= 2(2)(3)
16 = (2)(2)(2)2)
LCM = 2(2)(2)(2)(3)(5) = 240
2007-04-18 21:07:42 · answer #9 · answered by richardwptljc 6 · 1⤊ 1⤋
10=2*5
12=2^2*3
16=2^4
LCM=2^4*3*5
LCM=240
2007-04-18 21:09:57 · answer #10 · answered by yupchagee 7 · 0⤊ 1⤋