For like Sodium Hydrate NaOH there are 2 types of bonds: the Na-O bond, which is ___% ( 1.5%) ionic and the O-H bond, which is ____( 0.5%) ionic. So the OH-1 ion is held together by a blank ___ and the sodium is attached by ____ bond.
What are the blanks?! The first two blanks (1.5 and .5), i calculated by myself, but i am not sure if they are right or wrong!! PLEASE HELP!!
the ionization energies are: Na=0.93-O=3.44 = a difference of 2.51 electro negativity and then the percent ionic on the table would be in between 1 and 2 %.
Any ideaS?!!
2007-04-18 13:14:29 · 2 answers · asked by abe_cooldude 1 in Science & Mathematics ➔ Chemistry
then O=3.44- H=2.20= a difference of 1.24 ( percent difference of 2%)
2007-04-18 13:16:02 · update #1
I don't know what table you are looking at, but a large electronegativity difference (like that between Na and O) should give an ionic character of well over 50%, and the small difference between H and O should give a largely covalent bond. So O and H are bonded covalently, and Na and OH are bonded ionically.
2007-04-18 20:14:10 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋
because ionic bonds, via definition, are bonds between ions there must be a minimum of one + ion and one - ion and hence a +end and a - end to the bond (polar). there is not any such element as a non-polar ionic bond so "polar ionic" is redundant.
2016-12-04 06:55:22 · answer #2 · answered by abila 4 · 0⤊ 0⤋