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It says to find the difference of two squares?

b^2-14b+49

And

6m^2-150

Can someone explain how to do it??

2007-04-18 12:10:00 · 6 answers · asked by Cyanide 3 in Education & Reference Homework Help

6 answers

b^2-14b+49
(b-7)^2

6m^2-150
6(m^2-25)
6(m-5)(m+5)

2007-04-18 12:18:13 · answer #1 · answered by Dave aka Spider Monkey 7 · 1 0

Well....the equation(s) are a^2 - b^2=(a+b)(a-b)
It's confusing...i know. So for the first, it'd be (b+7)(b-7) cuz u have to follow the equation and find the perfect square of 49.

For the second, you would have to take out a common factor which would be 3. SO ur equation would read 6(m^2-25)
And since 50 has a perfect square of 5 the answer would be 6(m+5)(m-5) Hope that helps!!

2007-04-18 12:29:56 · answer #2 · answered by v.ballerr <3 5 · 1 1

The first one is a perfect square trinomial, and it is factored correctly by one of the other posters.

the second one will be the difference of two squares when you factor out the common 6

2007-04-18 12:58:17 · answer #3 · answered by bluekitty1541 4 · 0 0

you could, that's purely that do it you will choose complicated numbers. Extending the version of two squares: x² - a² = (x - a)(x + a) = (x - ?a²)(x + ?a²) x² + a² = x² - (-a²) = (x - ?(-a²))(x + ?(-a²)) = (x - ai)(x + ai) observe -a² ? (-a)²

2016-12-10 05:44:18 · answer #4 · answered by klohs 4 · 0 0

Ok what you do first is
oh nevermind! they are both prime. that means that they look like prime rib when you think about them with your eyes closed!

2007-04-18 12:18:03 · answer #5 · answered by Anonymous · 0 1

visit
www.algebra.com

2007-04-18 12:18:03 · answer #6 · answered by Sabari Nair 2 · 0 0

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