jennifer has a total of 11 coins all quarters and dimes?

Question

the total value of the coin is 1.85 how many of each coin does she have???

Answer 1

.10 * x + .25 * (11 - x ) = 1.85
.10 * x + 2.75 - .25 * x = 1.85
-.15 * x = -.9
x = 6

So, 6 dimes and 5 quarters.

Answer 2

Let Q be the number of quarters and D the number of dimes. Then since there are 11 coins total, Q + D = 11. And if their total value is $1.85 then adding up the cents gives 25Q + 10D = 185.

You now have two equations with two unknowns, so solve the system for Q and D using a method such as substitution.

Answer 3

The coin economic employer contains 13 dimes and 10 quarters form of dimes = x form of quarters = y (x * 0.10) + (y * 0.25) = 3.80 (4 * x ) + (10 * y ) = 152 x + y = 23 x = 23 - y 4x = ninety 2 - 4y ninety 2 - 4y + 10y = 152 6y=60 so y = 10 and for this reason x = 13 --------------------------------------... The rectangle is 22 inches lengthy and six inches huge 2 * length + 2 * width = fifty six length + width = 28 length = 4 + (3 * width) 4 + (3 * width) + width = 28 4 * width = 28 - 4 = 24 width = 6 length = 4 + (3 * 6) = 22 --------------------------------------... A pizza expenditures $12 and a salad expenditures $5 2 pizzas + a million salad = 29 so 4 pizzas + 2 salads = fifty 8 so 2 salads = fifty 8 - 4 pizzas 3 pizzas + 2 salads = 40 six 3 pizzas + fifty 8 - 4 pizzas = 40 six a million pizza = fifty 8 - 40 six = 12 2 pizzas + a million salad = 29 (2 * 12) + a million salad = 29 Salad = 29 - 24 = 5

Answer 4

If jennifer had all 11 quarters she would have $2.75,which is $0.90 more than what she has.
This difference is there because she had some dimes also and the difference of values of a quarter and a dime is $0.15
Therefore no of dimes=0.90/0.15=6
and the no of quarters is 11-6=5

Answer 5

Put :

x = number of dimes
y = number of quarters

First step:

1) x + y = 11
2) .10x +.25y = 1.85

Multiply equation 1) by ( -.10) and added equation 1)' and 2):

1)' -.10x -.10y = -.10(11)
2) -.10x +25y = 1.85
----------------------------
.15y = .75
y = 5

Second step:

You substitute y = 5 in equation 1)

We obtain : x + 5 = 11 => x = 6


Verification

1) 6 + 5 = 11
2) .10(6) + .25(5) = 1.85 => .60 + 1.25 = 1.85

Final answer : 6 dimes and 5 quarters

Answer 6

5 quarters 6 dimes

Answer 7

let

x = amount of dimes

y = amount of quarters

11 = total amount of dimes and quarters

0.1x = value of dimes

0.25y = value of quarters

1.85 = value of dimes and quarters

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x + y = 11- - - - - - - - - - - -Equation1
0.1x + 0.25y = 1.85- - - - Eqyatuib 2
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Substitute Method equation 1

x + y = 11

x + y - x = - x + 11

y = - x + 11

Substitute the y value into equation 2

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0.1x + 0.25y = 1.85

0.1x + 0.25(- x + 11) = 1.85

0.1x + (- 0.25 + 2.75) = 1.85

0.1x - 0.25x + 2.75 = 1.85

- 0.15x + 2.75 = 1.85

- 0.15x + 2.75 - 2.75 = 1.85 - 2.75

- 0.15x = - 0.9

-0.15x / - 0.15 = - 9 / - 0.15

x = - 9 / - 0.15

x = 6

Insert the x value into equation 1

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x + y = 11

6 + y = 11

6 + y - 6 = 11 - 6

y = 5

Insert the y value into equation 1

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Check for equation 1

x + y = 11

6 + 5 = 11

11 = 11

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Check for equation 2

0.1x + 0.25y = 1.85

0.1(6) + 0.25(5) = 1.85

0.6 + 1.25 = 1.85

1.85 = 1.85

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Both equations balance

The solution set { 6, 5 }

- - - - - - - - -s-

Answer 8

5 quarters and 6 dimes

Answer 9

6 dimes, 5 quarters

Answer 10

q+d=11 so d=11-q
.25q+.1d=1.85 so 2.5q+d=18.5
2.5q+11-q=18.5
1.5q+11=18.5
1.5q=7.5
q=5 so d=6 cuz 6+5=11
Thus there are 5 quarters and 6 dimes.