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I haven't practiced my algebra in a while, here's an example of what I mean. It's the physics equation:
Qcold = -Qhot
or : (mc dT) = -(mc dT)
with all the numbers plugged in, and I'm trying to find the final temperature : Tf

How do I get Tf on one side of the equation? A step by step solution is much appreciated, thanks.

24.0kg(4186 J/kg C)(Tf - 25.0 C) = -1.50kg (448 J/kg C)(Tf - 610 C)

2007-04-18 12:02:21 · 1 answers · asked by chrisamethyst 4 in Science & Mathematics Physics

1 answers

Not to worry. Just do a bit of algebra. Start by ignoring all of the units
(I am assuming that you have the correct starting equation)
24.0*4186*(Tf - 25.0) = -1.50*448*(Tf - 610)

simplify a bit

100464*(Tf-25)=-672*(Tf-610)
a bit more algebra

(100464+672)*Tf=
100464*25+672*610

101136*Tf=2921520

Tf=28.9 C

j

2007-04-18 17:12:37 · answer #1 · answered by odu83 7 · 0 0

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