Help me with this slope equation please?!?

Question

Alright i am not sure how to do this! But tomorrow we have a large test :/. Any way

If i have

1/2y=1/2x how do i find the

1.) Slope
2.) Slope y-intercept equation
3.) y-intercept
4.) x-intercept
5.) one additional point on the line
6.) A line parallel to original line
7.) Equation of a line perpendicular of original line.
8.) And the standard Equation for it.

And another one... if i had the ordered pair (5,-2),(4,3) how do i find the same things as above

1.) Slope
2.) Slope y-intercept equation
3.) y-intercept
4.) x-intercept
5.) one additional point on the line
6.) A line parallel to original line
7.) Equation of a line perpendicular of original line.
8.) And the standard Equation for it.

Answer 1

1/2y=1/2x so y=x
point slope formula is y=mx+b, where m is the slope, and b is the y-intercept. So:
y=1x+0
1) Slope is 1
2) Slope y-intercept equation is y=1x+0
3) Plug in 0 for x, you get y=0. y-intercept is 0
4) Plug in 0 for y. you get x=0. x-intercept is 0
5) Plug in an x to get y. In this case x=4, gets y=4. So point on line is (4,4).
6) Parallel lines have same slope and different y-intercepts, so y=1x+5
7) Perpendicular lines have negative reciperical slopes (turn it upside down and change the positive/negative sign). In this case, y=-1x
8) y=x is the standard equation

1) Find slope by with the equation (y-y')/(x-x') where one ordered pair is (x,y) and the other ordered pair is (x',y').
So, (-2-3)/(5-4)=(-5)/1. So slope is -5
2) To find y-intercept equation, pick one ordered pair.
3=(-5)(4)+b so 3=-20+b so b=23. y=-5x+23
3) y-intercept is 23
4) x-intercept is 23/5
5) (1,18)
6) Parallel line is y=-5x+10
7) Perpendicual line is y=1/5x+10
8) Standard equation is y=-5x+23

Answer 2

the slope equation is Y=mx +b.

Where m is the slope and b is the y intecept.

if y/2 = x/2 then the equation becomes Y=(1)x + 0
1 is the slope and it passes through point 0,0.

for the second one the slope m can be figured by delta y / delta x or (5-4) / (-2-3) = 1 / -5 or neg 1/5th

therefore Y = (-1/5 x) + b

substitute any of the coordinates into the equation and solve for b (the y intercept) the rest is up to you.

Answer 3

the first one is easy

1/2y=1/2x
divide both sides by 1/2 so u get
y=x

then the slope is positive 1
slope intercept is 0 the (middle of ur graph)
y intercept is 0 since it crosses at 0
and x intercept is 0 also since it croses at 0
an additional point is 2
a line parrelel would be y=x+2
a perpendicular line would be y=2x
the standard equation would be ax+by=c or somethin liek that
so it would be x+y=0

Answer 4

1/2y =1/2x --> y=x
Slope =1 because it is the number multiplying x
y=x since slope =1 and y-intercept = 0
y-intercept =0
x-intercept = 0
(1,1)
y=x+1
y=-x
-x+y=0

Slope = (3-(-2))/(4-5) = -1
y = -x +b, so 3= -4 +b, so b= 7, so y=-x+7
b = 7 = y-intercept
0=-x+7 so x+7 is x - intercept
(5,2)
y= -x +9
y=x+7
x+y -7 = 0

Answer 5

shoulda thought of that when you didn't pay attention in class