Hey, i need help finding the slope etc. HELP LOOK INSIDE PLEASE!?

Question

Alright i am not sure how to do this! But tomorrow we have a large test :/. Any way

If i have

1/2y=1/2x how do i find the

1.) Slope
2.) Slope y-intercept equation
3.) y-intercept
4.) x-intercept
5.) one additional point on the line
6.) A line parallel to original line
7.) Equation of a line perpendicular of original line.
8.) And the standard Equation for it.

And another one... if i had the ordered pair (5,-2),(4,3) how do i find the same things as above

1.) Slope
2.) Slope y-intercept equation
3.) y-intercept
4.) x-intercept
5.) one additional point on the line
6.) A line parallel to original line
7.) Equation of a line perpendicular of original line.
8.) And the standard Equation for it.

Answer 1

You need to express it as y=ax+b (in your case y=x)
slope=a (1)
y intercept is the point of y where x=0
x intercept is the point where y=0
Parallel lines have the same slop, ex y=x+3
perpen. lines have a slope of -(1/a) , ex y=-x+2
Standard eq, I think is in the form ax+by+c = 0