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8 answers

Death Valley is at a lower altitude, and there is more air above it.

More air, more weight pressing down from above, more pressure.

The same principle works in a pool between the shallow and deep end.

2007-04-18 07:55:46 · answer #1 · answered by Anonymous · 1 0

Using Bernoulli's equation that basically states pressure varies with depth, the difference in pressure between Denver (P2) and Death Valley (P1) will be the change in height between the two

P2 = P1 + (density of air)*(acceleration due to gravity)*(height difference between P2 and P1)

2007-04-18 07:57:08 · answer #2 · answered by Anonymous · 0 0

Of course scythian's answer is the one you are looking for. But for ordinary uses, scales that measure "weight" are actually calibrated with standard masses. So if you can get the buyer in Death Valley to accept your scale (that was calibrated in Denver), instead of his own scale, calibrated in Death Valley, you have a sucker on the hook, and you might as well tweak your scale and pocket a few grams, making your profit perhaps hundreds of dollars XD

2016-05-18 01:31:55 · answer #3 · answered by lindsay 3 · 0 0

Elevation

2007-04-18 08:03:28 · answer #4 · answered by Anonymous · 0 0

Because they have drastically different altitudes, and this has a large effect on the air pressure.

2007-04-18 08:01:27 · answer #5 · answered by Tommy R 2 · 0 0

It really depends on the weather at both places but a simple answer is altitude.

2007-04-18 07:54:39 · answer #6 · answered by Gene 7 · 0 0

altitude

2007-04-18 08:01:16 · answer #7 · answered by Anonymous · 0 0

well it has to do with the elavation of the land

2007-04-18 08:15:06 · answer #8 · answered by Anonymous · 0 0

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