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A large turntable rotates about a fixed vertical axis, making one revolution in a time of 6.40 s. The moment of inertia of the turntable about this axis is 1300 kg*m^2. A child with a mass of 44.0 kg, initially standing at the center of the turntable, runs out along a radius.

Part A) What is the angular speed of the turntable when the child is a distance of 1.90 m from the center? (Assume that you can treat the child as a particle.)

I have no clue how to solve this problem?

2007-04-18 07:24:15 · 1 answers · asked by ? 1 in Science & Mathematics Physics

1 answers

I think they want you to assume no friction and no forces to maintain the rotation. Treat it as a conservation of angular momentum problem. The moment of inertia of the system turntable + child increases as the child moves outward so the rate of rotation will decrease.

2007-04-18 09:26:39 · answer #1 · answered by meg 7 · 0 0

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