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Martha leaves home at 9 AM, bicycling at a rate of 24 miles per hour. Two hours later, john leaves, driving at a rate of 48 miles per hour. At what time will John catch up with Martha?

2007-04-18 05:59:06 · 11 answers · asked by Anonymous in Science & Mathematics Mathematics

11 answers

Let they meet at distance of d miles from start.
Time required Martha to reach distance d, t (martha) = d /24
Time required Martha to reach distance d, t (Jhon) = d /48 + 2 hr.
so d/ 24 – d /48 = 2
Solving this distance = 96 miles
Time required to travel this distance by Marth = 96 / 24 = 4 hours
They will meet at 1 PM

2007-04-18 06:05:31 · answer #1 · answered by Pranil 7 · 0 0

Martha has a two hour head start during which time she rides 24 x 2 = 48 miles. Figure out how many miles per hour faster John can drive, and divide 48 by this to see how many hours it takes him to catch up.

2007-04-18 06:06:33 · answer #2 · answered by hayharbr 7 · 0 0

You need to break this up into two parts. The distance Martha travels and the distance that John travels, all based on the time that John takes.

Since Martha travels at a rate of 24 miles per hour and leaves 2 hours ahead of John. we use the formula distance is rate times the time. or in her case.

dm = (24t+48) the extra 48 miles takes into consideration the 2 hour head start.

The distance John travels is modeled by

dj = (48t)

Set these two equations equal to each other and solved for t.

2007-04-18 06:06:12 · answer #3 · answered by nmhawthorne 1 · 0 0

1:00 pm John catches Martha.

2007-04-18 06:09:07 · answer #4 · answered by dwinbaycity 5 · 1 0

let t be time Martha bikes. t-2 is John's time. distance = rate * time, and distances are equal, so
24t = 48(t-2)
24t = 48t - 96
24t = 96
t = 4.
So John catches Martha (author of this question remembers a certain commercial from 1959 or 1960) at 1 pm.

2007-04-18 06:07:57 · answer #5 · answered by Philo 7 · 1 0

it can be espressed as
Martha
y=24x
John
y=48(x-2)
so
24x=48(x-2)
24x=48x-96
-24x=-96
24x=96
x=4

so John will catch martha at 1 PM or 4 hrs after Martha left and they both would have traveled 96 miles

2007-04-18 06:39:26 · answer #6 · answered by diablo_gjones 2 · 0 0

let x=number of hours martha rides. x-2=john's hours

24(x)=48(x-2)
24x=48x-96
96=24x
4=x

so, 1 pm

check:
martha 4x24=96
John 2x48= 96 so it works

2007-04-18 06:11:26 · answer #7 · answered by kelsey 7 · 0 0

john will reach martha at 1pm after each tarvels 96 miles

2007-04-18 06:06:54 · answer #8 · answered by Anonymous · 1 0

And... once you're asking while John will capture up...2 hours. once you're asking if John can extremely journey a motorbike ninety six miles at 40 8 miles an hour while not having a heart attack. in all possibility no longer.

2016-12-10 05:25:06 · answer #9 · answered by ? 4 · 0 0

1 pm

2007-04-18 06:07:41 · answer #10 · answered by premed student 2 · 1 0

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