i just cant seem to understand how it transforms. Any help would be great, exam is tomorrow. thanx
vp/vs=np/ns
transformed so that vs is the subject
vs= vp X ns /np
2007-04-15 09:16:00 · 6 answers · asked by Rebecca G 1 in Science & Mathematics ➔ Engineering
There are lots of routes. Here's one.
Multiply both sides by vs
vp = (vs*np) / ns
divide both sides by np
vp/np = vs/ns
multiple both sides by ns
(vp*ns)/np = vs
or
vs = (vp * ns)/np
2007-04-15 09:27:05 · answer #1 · answered by anotherbsdparent 5 · 0⤊ 0⤋
VP/VS=NP/NS
Do 1 over the whole equation
VS/VP=NS/NP
Now multiply both sides by VP
VS = VP*N5/NP
2007-04-15 09:22:16 · answer #2 · answered by ibs 4 · 0⤊ 0⤋
vp/vs = np/ns
Cross multiply to get (vp x ns) = (vs x np)
Therefore:....vs = (vp x ns) ÷ np
2007-04-15 10:05:18 · answer #3 · answered by Norrie 7 · 0⤊ 0⤋
It's easy to see if you write it out on paper with one term above the line (dividend) and one below (divisor), but the names don't matter.
Now you can move any of the terms from one side to the other but if you do they must also swap positions above or below the line(i.e they move diagonally). If you leave an empty space above a line you must replace it with a 1.
You can also invert both sides if this helps.
2007-04-18 10:00:09 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Voltage primary is to voltage secondary = turns primary is to turns secondary.
If the primary to secondary is 10 to 1 then the turns should have the same ratio
Or u can reverse the ratio
2007-04-15 12:12:52 · answer #5 · answered by JOHNNIE B 7 · 0⤊ 0⤋
ahhh i don't have a clue!! LOL
2007-04-15 09:19:17 · answer #6 · answered by Anonymous · 0⤊ 0⤋