Evaluate
4(a-2)2 when a=7
2007-04-12 23:55:17 · 16 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
40
2007-04-12 23:57:22 · answer #1 · answered by Winter Angel 2 · 1⤊ 0⤋
4(7-2)2 = 4 x 5 x 2 = 40
2007-04-15 06:30:02 · answer #2 · answered by little lady 1 · 0⤊ 0⤋
4(a-2)2
If a = 7
Then
4(7-2)2
becomes
4(5)2
= 40
2007-04-13 01:01:51 · answer #3 · answered by Rod Mac 5 · 0⤊ 0⤋
"4(a-2)2, when a = 7" is the same as:
"4 x 5 x 2", which is 40.
2007-04-14 00:12:39 · answer #4 · answered by vanilladay 2 · 0⤊ 0⤋
4(a-2)2 when a=7
4(a-2)2 =
8(a-2) =
8a - 16 =
8*7 - 16 =
56 - 16 = 40
Is the second two ment to be a square ? If so, then:
4(a-2)² when a=7
4(a-2)² =
4(a² -2a -2a +4) =
4(a² -4a + 4) =
4(7² - 4*7 + 4) =
4(49 - 28 + 4) =
4(53 - 28) =
4(25) = 100
2007-04-13 00:07:58 · answer #5 · answered by Brenmore 5 · 0⤊ 0⤋
If we write it as 4 X (a-2) X 2 = 8a - 16, and given a = 7, we get 8a - 16 = 56 - 16 = 40
If it is 4 (a - 2)^2 i.e. (a - 2) square, then we have
4 ( 7 - 2 ) ^2 = 4 X 25 = 100
2007-04-13 00:00:14 · answer #6 · answered by Swamy 7 · 0⤊ 0⤋
Try this:
4 (7 - 2)2 = 4(5)2 = 40
I have simply substituted the value of a = 7.
Hope this helps and don't forget to vote for this answer!!
2007-04-13 10:20:43 · answer #7 · answered by Anonymous · 0⤊ 0⤋
4(a-2)2
4(7-2)2
4(5)2
20x2
=40
remember; BDMAS
2007-04-13 00:04:06 · answer #8 · answered by same 203 1 · 0⤊ 0⤋
4*(7-2)*2
4*2*(7-2)
8*(5)
8*5 = 40
2007-04-13 03:30:10 · answer #9 · answered by Siale r 1 · 0⤊ 0⤋
4(a-2)2 when a=7
4(7-2)2 always do brackets first
4(5)2
=4*5*2
=40
2007-04-12 23:59:04 · answer #10 · answered by mrs r 2 · 0⤊ 0⤋