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2 answers

Use partial reactions

Sn -> Sn2+ + 2e-

NO3- + 4H+ + 3e- -> NO + 2H2O

Multiply i) by 3 and ii) by 2 and add.

3Sn + 8HNO3 -> 3Sn(NO3)2 + 2NO + 4H2O

2007-04-12 20:02:48 · answer #1 · answered by ag_iitkgp 7 · 1 0

Try 8HNO3 .

It will work!

2007-04-13 02:58:05 · answer #2 · answered by Gervald F 7 · 0 0

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