Can someone please help me set this up?Two planes start from the same point and fly in opposite directions.?

Question

The first plane is flying 50 miles per hour slower than the second plane. In 2.5 hours, the planes are 1400 miles apart. Find the rate of each plane.

Answer 1

dist = (rate) times (time)

first plane rate = r
second plane rate = r-50
time = 2.5
distance = 1400
2.5r + 2.5 (r-50) = 1400
5r - 125 = 1400
5r = 1275
r = 255
other plane 50 slower 255-50

rates are 255mph and 205mph

Answer 2

Define the speed of plane 2 as X mph so plane 1's speed is X-50 mph.

In 2.5 hours, plane 1 traveled 2.5 * (X-50) miles and plane 2 traveled 2.5 * X miles.

Since they traveled in opposite directions, the planes are 2.5 * (X-50) + 2.5 * X miles apart or 5X-125 miles.

Since the planes are 1400 miles apart 5X-125=1400 so X=305.

Plane 2 travels 305 mph and plane 2 travels 255 mph.

Answer 3

Let
r - 50 = rate of first plane
r = rate of second plane

distance = rate x time

The planes are separating at the combined speeds of the two planes.

d = [(r - 50) + r]*t

1400 = 2.5(2r - 50)
560 = 2r - 50
610 = 2r
r = 305
r - 50 = 305 - 50 = 255

So the speeds of the two planes are 255 mph and 305 mph.