Graphing Quadratic Functions y= -x2+3?

Question

how do you solve this equation so that you can graph it?

Answer 1

This is a parabola with vertex (0,3) x intercepts +-sqrt3 and opening downwards.y intercept at(0,3

Answer 2

I truly do not understand what steps your instructor instructed you have to be first. the following is what i ought to do: y = -x^2 - 4x - 3 = (-a million)(x^2+4x+3) = (-a million)(x+3)(x+a million). that's 0 (i.e. y=0) at the same time as x=-3 or x=-a million for this reason (-3,0) and (-a million,0) are on the graph and are the x-intercepts. Plot them and see that (-2,0) is halfway between them. for this reason x=-2 is on the axis of the parabola. Plug in x=-2 and discover that (-2, a million) is the vertex. The parabola opens downward because the coefficient of x^2 is adverse. finally, if x=0, y=-3 so the y-intercept is (0,-3). you at the moment have 4 factors on the curve. Plot them and draw a comfortable curve by ability of them.

Answer 3

for a graph, go to http://www.calculator.com/calcs/GCalc.html

type in -(x^2) + 3, if you don't want the (), then you will have to type it in like this -1x^2 + 3, or else it won't turn out like its suppose to.