How many grams of Hydrogen gas can be collected from 500 g of zinc if an unlimited amount of HCl is available?

Question

i don't understand how to do this problem and if someone could show me how to do it step by step, it would be greatly appreciated. thanks.

Answer 1

Zn + 2HCl ===> ZnCl2 + H2(g)
Atomic weights: Zn=65.4 H=1.00

500gZn x 1molZn/65.4gZn x 1molH2/1molZn x 2gH2/1molH2 = (500)(2)/(65.4) = 15.3gH2

The 500g Zn is given. The first factor comes from the atomic weight. The grams zinc cancel, leaving moles Zn. The second factor comes from the balanced equation. The moles Zn cancel, leaving moles H2. The third factor comes from the molecular weight. The moles H2 cancel, leaving grams H2.

Answer 2

Zn+2HCl=ZnCl2+H2


V(H2)=22.4*500/65.4=171.3 l

Answer 3

first write a balanced eqaution like this

Zn +2HCl----ZnCl2+H2

now the atomic wt of Zn is 65.4 and that of H is 1 so the eqaution will be like this

Zn(65.4g) +2HCl----ZnCl2+H2(2g)

if 65.4g Zn produces 2g of H then

500g Zn will produce =2x500/65.4 =15.3