Evalute an Integral?

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Evalute an Integral?

int{ 2 } ^ { 5 } (6x^2 -10x + 2) dx

2007-04-12 14:15:46 · 3 answers · asked by bhicks 1 in Science & Mathematics ➔ Mathematics

3 answers

2x^3 - 5x^2 + 2x from 2 to 5
= (250 - 125 + 10) - (16 - 20 + 4)
=135

2007-04-12 15:14:02 · answer #1 · answered by Kathleen K 7 · 0⤊ 0⤋

This should be like shooting monkeys in a barrel.
The integral is 2x^3-5x^2+2x
Evaluated at 2, 16-20+4 = 0
Evaluated at 5, 250-125+10= 135
With limits of 2 and 5, the integral is 135

2007-04-12 21:22:09 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋

int { 2 to 5 } [6x^2 -10x + 2] dx

= [2x^3 - 5x^2 + 2x] { 2 to 5 }

=[2(5)^3 - 5(5)^2 + 2(5)] - [2(2)^3 - 5(2)^2 + 2(2)]
=[250 - 125 + 10] - [16 - 20 + 4]
=135

2007-04-12 21:21:26 · answer #3 · answered by Anonymous · 0⤊ 0⤋