Two added to twice the reciprocal of a number is 12/5 . find the number?

Answer 1

2 + 2 *(1/x) = 12 / 5

2 * (1/x) = 12 / 5 - 2 = 2 / 5

1 / x = 1/5

x = 5

Answer 2

X (x+1)(2/x)=12/5

Answer 3

Find the missing value when two is added to twice the reciprocal of a number that equals 12/5.

First: write the given information into numerical data. In this case, the "x" variable represents the missing value. The reciprocal of "x" is 1/x

2 + 2(1/x) = 12/5

2 + (2*1)/x = 12/5

2 + 2/x = 12/5

Sec: eliminate fractions - multiply the denominators with each term.

(5x)(2) + (5x)(2/x) = (5x)(12/5)

*Cross cancel "like" terms & combine the remaining terms.

10x + (5)(2) = (x)(12)

10x + 10 = 12x

Or, 12x = 10x + 10

Third: combine "like" terms - subtract 10x from both sides (when you move a term to the opposite side, always use the opposite sign).

12x -10x = 10x -10x + 10

12x - 10x = 10

2x = 10

Fourth: isolate "x" on one side by dividing both sides by 2.

2x/2 = 10/2

x = 10/2

x = 5

Answer 4

2 + 2/n = 12/5 Multiply by 5n.
10n + 10 = 12n
10 = 2n
5 = n

Check
2 + 2/5 = 12/5
10/5 + 2/5 = 12/5 Correct

Answer 5

2/1 + 10/ 24 i got 58/ 24 witch is 2 10/24 simplified is 1 5/12

Answer 6

5

2+2(x^-1)= 12/5
2(x^-1)=2/5
x^-1=1/5
x= 5