A Parabola with Vertex (0,4) and zeros -6 and 6 in factored form would be y=1/8(x-6)(x+6) and would open up right?...
so y=1/8(x-6(x+6) is wrong..so what would be the steps to finding the correct factored form...
P.S. ty for help with the vertex
2007-04-12 12:38:05 · 3 answers · asked by J-Rome 2 in Science & Mathematics ➔ Mathematics
p and q wuld be -6 and 6? and x and y would be vertex coords?
2007-04-12 12:54:50 · update #1
y=a(x-s)(x-t)
4=a(-6)(6)
4=-36a
4/36=a
1/9=a
1/9 would give me a parabola opening...up...but...it should be opening down...and it should be -1/9...which is the right answer...how would you get that?
2007-04-12 12:58:06 · update #2
having zeros at -6 and 6 means the points (6,0) and (-6,0) are part of the parabola. Since the vertex is at (0,4), the parabola must open down to go through the other points.
2007-04-12 12:43:34 · answer #1 · answered by Demiurge42 7 · 0⤊ 0⤋
The parabola would open down, because the vertex is higher on the y-axis than the zeros.
2007-04-12 12:46:29 · answer #2 · answered by Nick R 4 · 0⤊ 0⤋
Y=a(x-p)(x-q)
That's the general factored form.
Hope that helps. Yay!
2007-04-12 12:43:14 · answer #3 · answered by Cosplayer! 4 · 0⤊ 0⤋